G Gabriel

02-26-2007, 02:11 PM

?mod(2,3)

=2

How so?

=2

How so?

View Full Version : Mod()...?

ABC123

G Gabriel

02-26-2007, 02:11 PM

?mod(2,3)

=2

How so?

=2

How so?

Selwyn Rabins

02-26-2007, 02:16 PM

?mod(2,3)

=2

How so?

it is correct. 3 goes into 2 zero times with a remainder of 2.

=2

How so?

it is correct. 3 goes into 2 zero times with a remainder of 2.

G Gabriel

02-26-2007, 02:22 PM

Selwyn;

Thanks. I knew it's correct but was not sure if it is the right explantion.

Thanks. I knew it's correct but was not sure if it is the right explantion.

gschepp

02-26-2007, 02:23 PM

I would imagine that 3 goes into 2 (or 20) 6 times making it 20-18 =2

gschepp

02-26-2007, 02:25 PM

Ahh that's how it works when number size is reversed

G Gabriel

02-26-2007, 02:25 PM

Gary:

No, that explanation won't work.

?mod(1,8)

=1

No, that explanation won't work.

?mod(1,8)

=1

csda1

02-26-2007, 02:54 PM

INT(1/8)=0 with remainder of 1. 1 is the answer

mod(x,n) is equivalent to

x-(INT(x/n)*n)

Negative numbers also work, although the result is negative (as it should be)

mod(x,n) is equivalent to

x-(INT(x/n)*n)

Negative numbers also work, although the result is negative (as it should be)

G Gabriel

02-26-2007, 03:09 PM

?mod(34,4)

=2

?mod(-34,4)

=2

=2

?mod(-34,4)

=2

AaronBBrown

02-27-2007, 10:33 AM

Selwyn;

Thanks. I knew it's correct but was not sure if it is the right explantion.

Actually, it is the right explanation. If you need further explanation on how modulo operations work, google will provide you with a number of links.

Thanks. I knew it's correct but was not sure if it is the right explantion.

Actually, it is the right explanation. If you need further explanation on how modulo operations work, google will provide you with a number of links.

G Gabriel

02-27-2007, 10:43 AM

Aaron:

Thanks. I realized after Selwyn's reply that it is the right explanation. When I posted the question, I wasn't sure.

Thanks. I realized after Selwyn's reply that it is the right explanation. When I posted the question, I wasn't sure.

Powered by vBulletin® Version 4.2.5 Copyright © 2018 vBulletin Solutions Inc. All rights reserved.