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Week Ending function (Pay Period)

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    Week Ending function (Pay Period)

    I had an application last week where I needed to calculate the date of the first day of the week that an event occurred it. That expression DATE - DAY_NUMBER(CDOW(DATE)) (provided by GGhandi) works fine.

    But now I have an odd request, and I'm not sure how to modify the above expression (if at all possible) to get this calculation to work.

    In this instance, I need to calculate the date of the ending of a pay period that ends on Thursday each week. (In other words, the start of the pay week is every Friday, and ends on the following Thursday.)

    So for example, in this month of June 2016, whether an employee works on Friday 06/26/16 or Tuesday 06/28/16, it would still fall within the pay week which ends on Thursday 06/30/16.

    Any thoughts as to how I could accomplish this?

    Thanks,
    Rich
    Sergeant Richard Hartnett
    Hyattsville City Police Department
    Maryland

    #2
    Re: Week Ending function (Pay Period)

    Code:
    dim pay_week as d
    dim pay_day as d
    pay_week = pay_day+(5-day_number(cdow(pay_day)))
    dim dd as d

    dd = {06/26/2016}+(5-day_number(cdow({06/26/2016})))
    ?dd
    = {06/30/2016}
    Last edited by GGandhi; June 25, 2016, 03:36 PM.
    thanks for reading

    gandhi

    version 11 3381 - 4096
    mysql backend
    http://www.alphawebprogramming.blogspot.com
    [email protected]
    Skype:[email protected]
    1 914 924 5171

    Comment


      #3
      Re: Week Ending function (Pay Period)

      Thanks for the quick response G.

      I'm a little lost on the "Pay_Date" though. Is that the day the employee worked? If not, where does that date come from?
      Sergeant Richard Hartnett
      Hyattsville City Police Department
      Maryland

      Comment


        #4
        Re: Week Ending function (Pay Period)

        pay_date or the day_employee_worked
        i added the example to my code above take a look

        dim dd as d

        dd = {06/26/2016}+(5-day_number(cdow({06/26/2016})))
        ?dd
        = {06/30/2016}
        Code:
        dim date_employee_worked as d
        dim pay_week_of as d
        pay_week_of = date_employee_worked +(5-day_number(cdow(date_employee_worked)))
        to make it clear

        edit:
        while testing I do find some inconstancy,
        I will repost the calculation in a minute
        Last edited by GGandhi; June 25, 2016, 04:40 PM.
        thanks for reading

        gandhi

        version 11 3381 - 4096
        mysql backend
        http://www.alphawebprogramming.blogspot.com
        [email protected]
        Skype:[email protected]
        1 914 924 5171

        Comment


          #5
          Re: Week Ending function (Pay Period)

          the above did not work when the employee worked on Friday or Saturday, to correct I changed to a function

          Code:
          FUNCTION pay_week AS D (date_worked AS D )
          	dim d1 as n
          	dim d2 as n = 5
          	d1 = day_number(cdow(date_worked))
          	if d1 > 5 then 
          		d2 = 12
          	end if
          	pay_week = date_worked + (d2 - d1)
          END FUNCTION
          if you want one line code
          Code:
          dim date_worked as d
          dim week_of as d
          week_of = date_worked + (if(day_number(cdow(date_worked)) > 5, 12-day_number(cdow(date_worked)),5-day_number(cdow(date_worked))))
          Last edited by GGandhi; June 25, 2016, 05:54 PM.
          thanks for reading

          gandhi

          version 11 3381 - 4096
          mysql backend
          http://www.alphawebprogramming.blogspot.com
          [email protected]
          Skype:[email protected]
          1 914 924 5171

          Comment


            #6
            Re: Week Ending function (Pay Period)

            That seems to work perfect!

            As always, thank you Gandhi.
            Sergeant Richard Hartnett
            Hyattsville City Police Department
            Maryland

            Comment

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