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Time Calculation help

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  • Time Calculation help

    = 09/20/2017 10:54:31 58 am

    = "20170920111141176"

    I used the cTime(Now()) function to convert NOW() to a character field in my table.

    Now I need to go the other way to get the following to work; convert my character field back to NOW() format.

    (below from NOW() documentation)

    dim t1 as T
    dim t2 as T
    t1 = now()
    t2 = now()
    ? t2-t1
    = 5.440000



  • #2
    Re: Time Calculation help

    See if this works.

    t = now()
    ? t
    = 09/20/2017 11:39:17 29 am
    ct = ctime(t)
    ? ct
    = "20170920113917290"
    ? ctodt(stod(left(ct,8))+" " +mask(substr(ct,9,7),"  :  :  ")+" "+substr(ct,15,2))
    = 09/20/2017 11:39:17 29 am
    There can be only one.


    • #3
      Re: Time Calculation help

      A bit shorter variation.

      t = now()
      ct = ctime(t)
      ? ct
      = "20170920154953494"
      bwd = mask(ct,"    /  /  |  :  :  |  ")
      ? ctodt(bwd)
      = 09/20/2017 03:49:53 49 pm
      There can be only one.


      • #4
        Re: Time Calculation help

        I bet it works. Won't have time to test till tomorrow; but I can follow it. I would not have thought about the mask function.


        • #5
          Re: Time Calculation help

          I couldn't wait. I tried it and it worked as I needed after substituting my fields.

          Thanks MUCH.

          ~ Tom


          • #6
            Re: Time Calculation help

            Apparently the date/time functions are pretty forgiving about the date portion. They manage to derive a date from "2017/09/20".

            dt = "20170920"
            ? mask(dt,"    /  /  ")
            = "2017/09/20"
            ? ctod(mask(dt,"    /  /  "))
            = {09/20/2017}
            and ctodt() handles it similarly.
            There can be only one.