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Three-field Selection/View/Filter/Grid puzzle

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  • Three-field Selection/View/Filter/Grid puzzle

    I've spent over a day playing with this on paper...

    In the SQL world, I think this is feasible with some convoluted joins, unions, select ins, select distincts, etc. But can someone explain how I might achieve my goal in this WAS application?

    Table looks fundamentally like this: (if preferable, this could be structured as a view, with linking tables - but I fared no better with that approach)

    (3 fields)

    x y z <--- column names

    1 A !
    1 A #
    1 B !
    2 A $
    3 B %
    4 C #
    4 D #
    5 E $
    6 C #

    I wish to display a grid containing only DISTINCT column y filtered primarily on column z. The actual arguments available to the select/filter process are both x and z. All distinct y for any submitted z should be displayed, however, a special display attribute should indicate where there is also a match on x. Therefore, a match on x is optional, but where there is a match, it must be somehow reflected in the display. (Each displayed y will be a link to a detail view of y.) A few examples:

    GenerateGrid(x=1, z="#")
    desired result:

    **A** (asterisks, or some other visual attribute indicating a match on x)
    C (notice C is displayed only once, though it matches on both x=4 and x=6)
    D

    GenerateGrid(x=1, z="$")
    desired result: (no match on x, so no special attribute)

    A
    E

    GenerateGrid(x=5, z="$")
    desired result:

    A
    **E**


    The first/biggest problem I've run in to is display of duplicate matches (as in first example). While there's an option for Unique Records Only, it seems inapplicable due to apparent necessity of including other columns in the filter/view.

    Or is this best solved via xbasic code? Any hints on how to implement that?

    [edit: I'm using standard .dbf for this; maybe an SQL db is the "no-brainer" answer?]
    Last edited by fsi; 07-07-2009, 10:03 AM.

  • #2
    Re: Three-field Selection/View/Filter/Grid puzzle

    Having received no response offering a solution for native .dbf, I worked out the following for standard SQL (in case anybody else has need).

    This is the verbose version (prior to elimination of WHERE in favor of JOIN). The _x_ tables are the linking tables, ARG1 and ARG2 are the "x" and "z" in the original post.

    select tblA.ID, 1
    from tblB, tblB_x_tblA, tblA, tblA_x_tblC, tblC
    where tblB.pkey = tblB_x_tblA.tblB_ID
    and tblB_x_tblA.tblA_ID = tblA.pkey
    and tblA.pkey = tblA_x_tblC.tblA_ID
    and tblA_X_tblC.id = tblC.pkey
    and tblB.pkey = ARG1 and tblC.pkey = ARG2
    union
    select tblA.ID, 0
    from tblA, tblA_x_tblC, tblC
    where tblA.pkey = tblA_x_tblC.tblA_ID
    and tblA_x_tblC.ID = tblC.pkey
    AND tblC.pkey = ARG2
    and tblA.ID not in
    (select tblA.ID
    from tblB, tblB_x_tblA, tblA, tblA_x_tblC, tblC
    where tblB.pkey = tblB_x_tblA.tblB_ID
    and tblB_x_tblA.tblA_ID = tblA.pkey
    and tblA.pkey = tblA_x_tblC.tblA_ID
    and tblA_X_tblC.id = tblC.pkey
    and tblB.pkey = ARG1 and tblC.pkey = ARG2)

    Two columns are returned, the actual result (A-E, as in initial post), together with a second column consisting of either 0 (inexact match) or 1 (exact match). Duplicates are prevented.
    Last edited by fsi; 07-12-2009, 11:34 AM.

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