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Filter Problem

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    Filter Problem

    Hello All!

    I have a simple parent/child set. I need to print a report of the child for certain records. The parent/child are linked by a field called "Conid".

    In writing the filter expression I am getting what I consider to be, strange errors.

    If I use: query.filter="conid=consumers->conid" the report works, but gives me more records than I need.

    If I use: query.filter= "isbilled = \"No\"" (where isbilled is a field in the child), it works, but gives me all of the records where this is so.

    If I try to combine them like: query.filter="conid=consumers->conid.and.isbilled = \"No\"" Alpha rejects this as an invalid filter.

    Why is this happening and how can I get this to work?


    Re: Filter Problem


    Please try this:

    query.filter="conid=consumers->conid .and. isbilled = 'No' "

    I am assuming that isbilled is character and not boolean, is that correct?

    and tell me if there is an error
    Gary S. Traub, Ph.D.


      Re: Filter Problem


      Often an easy solution when the desired filter includes fields from both parent and child tables (or child only) is to create a new set, inverting the relationship and using a one to one link. Do this, then base your report on the new set, using a filter that addresses the new parent table directly.


        Re: Filter Problem

        Originally posted by Charles Hoens View Post
        I have a simple parent/child set. I need to print a report of the child for certain records.
        Is that certain parent records or certain child records? Or both?
        If I use: query.filter="conid=consumers->conid" the report works, but gives me more records than I need.
        The report works? Not sure what that means.... you are testing a filter. Did the report deliver filtered records... ie did the filter work? I doubt it. That filter doesn't look any different than 1=1. I'm guessing you got more records than you needed because you got all the records.. maybe.

        Lets start with what you are trying to filter for... single parent and select child records, or something else?
        Mike W
        "I rebel in at least small things to express to the world that I have not completely surrendered"


          Re: Filter Problem

          First, Dr. Gary. I tried that expression also (actually first) and I got an error.

          Second, Tom. Humm. Sounds like a big workaround, but I always bow to you, the guru of filters. (I've used your examples for years with great success!)

          Third, Mike. Let me explain more fully. The parent dbf is called "Consumers" and is related to the child "Timehours" (One-to-Many) through a character filed called "Conid".

          I have a button on the set-form I am using to call the report. I need to print the Timehours records for just certain Timehours records for that particular consumer.


            Re: Filter Problem

            Some additional information:

            I got it to work by using the Alpha code plus an adjustment to the filter...

            'Print a report, label, letter, form or browse layout. You can specify which records to print.
            'Check to see if you are running the script from within a Form
            dim flag_error as l
            flag_error = .f.
            if is_object(topparent.this) then 
            	p = topparent.this
            	if eval_valid("P:CONTROL_BROWSE2:Conid.value") then 
            		DELETE Parameter1 
            		'Set the Parameter variable to the object's .value property
            		Parameter1 = eval("P:CONTROL_BROWSE2:Conid.value")
            		flag_error = .t.
            	end if 
            	flag_error = .t.
            end if 
            if flag_error then 
            	ui_msg_box("Error","CONTROL_BROWSE2:Conid does not exist. This script cannot be run in this context.",UI_STOP_SYMBOL)
            end if 
            filter = "conid = [varC->parameter1].and.isbilled='No'"  '<+++++ I added in the .and. isbilled='No'
            query.filter = replace_parameters(filter,local_variables())
            query.order = ""
            'Prompt user whether to print, or preview the layout. Set default to Print
            prompt_result = ui_get_print_or_preview("Print")
            If prompt_result = "Print" then
            Else if prompt_result = "Preview" then 
            End if
            Inside this code snippet I added to the filter ".and.isbilled='No'" Seems to be working now.




              Re: Filter Problem

              Did you try inverting the set?
              That would have been my first option.
              See our Hybrid Option here;

              We are the
              Department of Sunshine and Rainbows!

              Hope restored, faith renewed, spirits lifted!


                Re: Filter Problem

                Under context that you described, all the code in the action scripting that performs all the checks should not be needed.

                'acquire parent link value
                   dim vconid as C
                   vconid =  parentform:CONTROL_BROWSE2:Conid.value
                'create filter
                  dim vfilter as C
                  vfilter="conid = "+quote(vconid) + " .and. isbilled=\"NO\""
                  query.filter = vfilter
                  query.order = ""
                'Prompt user whether to print, or preview the layout. Set default to Print
                     prompt_result = ui_get_print_or_preview("Print")
                            if prompt_result = "Print" then
                            else if prompt_result = "Preview" then 
                            end if
                Mike W
                "I rebel in at least small things to express to the world that I have not completely surrendered"


                  Re: Filter Problem


                  Discernment is not needed in things that differ, but in those things that appear to be the same. - Miles Sanford