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why does this time function combination not work

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  • why does this time function combination not work

    I must be missing something, but it seems to me that the last expression and the second expression should resolve to the same value based upon the reference for totime() and toseconds() being midnight . Any explanations would be helpful.

    Code:
    dim t1 as Y
    
    t1 = now()
    ? t1
    = 10:39:13 23 am
    
    ? convert_type(t1,"c")
    = "10:39:13 23 am"
    
    ? totime(toseconds(convert_type(t1,"c")),2,0)
    = "11:01:03"
    Mike W
    __________________________
    "I rebel in at least small things to express to the world that I have not completely surrendered"

  • #2
    Re: why does this time function combination not work

    Mike,

    The culprit appears to be the 23 (presumably milliseconds) that Now() adds to the time string: 10:39:13 23 am. This fouls up toseconds()--or maybe it is convert_type that needs to lose the 23?. You won't have this problem if you use Time() instead of Now() but that should not be. Seems to me it is either a bug or there needs to be a new function to handle such a situation using Now().

    Ray

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    • #3
      Re: why does this time function combination not work

      Thanks Ray,
      I will report it as a bug, even though I tried it n v6-v9 and same applied. I would like to get a comment regarding this.

      This came about trying to add the difference between two time values to a third time value to achieve a new fourth time value. Subtracting time is easy, but adding is tricky. Especially when the functions give these type of results.
      Mike W
      __________________________
      "I rebel in at least small things to express to the world that I have not completely surrendered"

      Comment


      • #4
        Re: why does this time function combination not work

        No bugs.

        I must be missing something
        You are.

        dim t1 as Y
        t1 = now()
        Alpha is forgiving but not so forgiving.
        You dim'ed t1 as Y yet assigned it a T type value, hence the problem.

        Now try this:
        Code:
        dim t1 as y
        t1=time("0h:0m:0s",now())
        ?t1
        = 03:25:00 00 pm
        ?totime(toseconds(convert_type(t1,"c")),2,0)
        = "15:25:00"
        I see a question coming:
        If t1 is dim'd as Y why would alpha allow it to accept a T value? Isn't that a bug?

        That would be a philosophical question:
        You could say:
        It "did allow" it to accept a T value, hence it's a bug.
        Or, you could say:
        Not really, it did not. It only took a Y value out of the T value i.e. it's intuitive, it did you a favor ; hence it is not a bug.

        Now, you be the judge, is this a bug? Or not?
        I wouldn't call it a bug. Alpha has several "intutive" mechanisms.
        Maybe it's just a "lady bug", but don't push your luck.
        Last edited by G Gabriel; 08-11-2008, 09:03 PM.

        Comment


        • #5
          Re: why does this time function combination not work

          Gabriel,
          thanks!
          Mike W
          __________________________
          "I rebel in at least small things to express to the world that I have not completely surrendered"

          Comment


          • #6
            Re: why does this time function combination not work

            You'r welcome.

            Comment

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