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file.unzip() vs. unzip_files()

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  • file.unzip() vs. unzip_files()

    I think I must be missing something here. How does
    Code:
    file.unzip("c:\backup.zip", "*.*", "c:\temp")
    differ from
    Code:
    unzip_files("c:\backup.zip", "*.*", "c:\temp")
    and when would you use one vs. the other?

    -- Dick James

  • #2
    Re: file.unzip() vs. unzip_files()

    UNZIP_FILES() extracts files from Zipfile_Name, that match the Mask specification, to the Destination_Folder. The function is a high level wrapper around the FILE.UNZIP()method.
    There can be only one.

    Comment


    • #3
      Re: file.unzip() vs. unzip_files()

      Stan --

      Thanks for your response. I believe both code samples should extract all files in Zipfile_Name to the Destination_Folder. While Alpha's documentation says the function is a high level wrapper around the method, I don't understand how they differ from a usage standpoint. Don't they both do the same thing?

      Can you (or someone) help me understand the difference? Thanks.

      -- Dick James

      Comment


      • #4
        Re: file.unzip() vs. unzip_files()

        The reason I posted this question is that I encountered a problem where
        Code:
        file.unzip("c:\backup.zip", "*.*", "c:\temp")
        would not unzip all the files in a backup.zip file that was a little over 6 meg. I coded a work-around to extract the individual file names and then unzip them one at a time, but in so doing -- guess what? -- I discovered another command that appears to do the same thing as the first two in the previous post.

        Code:
        UNZIP_FILELIST( "c:\backup.zip", "", "c:\temp")
        I haven't tested this, but isn't it equivalent to the other two? Does anyone know of any differences between these? Does anyone know which is the recommended one to use?

        Comment


        • #5
          Re: file.unzip() vs. unzip_files()

          Stan,

          ...high level wrapper.......
          Please pardon my ignorance. In all these years of seeing this, I really never have understood what it means. Does it mean the wrapper just contains another function that it runs???
          Thanks for any clarification.
          Ernie

          Comment


          • #6
            Re: file.unzip() vs. unzip_files()

            By no means authority but I believe the answer is yes.

            Code:
            UNZIP_FILES( Zipfile_Name as C [, Mask as C [, Destination_Folder as C [, Preserve_Paths as L ]]] )
            The advantage of this function over

            Code:
            Result_Flag as L = FILE.UNZIP( Zip_Filename as C, Mask as C, Output_Directory as C  )
            seems to be the inclusion of the preserve_paths parameter.

            Suppose you were coding the unzip_files() function and found that the code in the file.unzip() method could have accepted the Preserve_Paths parameter but that it wasn't implemented (probably set a default for this in the original code). Makes sense to just create the new function by wrapping it in code to feed the Preserve_Paths parameter to the underlying code.
            There can be only one.

            Comment


            • #7
              Re: file.unzip() vs. unzip_files()

              Thanks for the explanation, Stan.
              Ernie

              Comment

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