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Age in yrs and months

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  • Age in yrs and months

    Many age functions have been posted here that calculate an age as of the system date for a given birth date. The following is a good one, probably based on something someone else posted here in the past:

    function Age as N(DOB as D)
    '**Note: blank b-days will =this yr, i.e., 2000 in 2000
    '**Future b-days will have negative ages
    '**Ages 1 month to 11 months will be 0 cuz only doing years here
    select
    case month(date())>month(dob)
    age=year(date())-year(dob)
    case month(date())=month(dob).and.day(date())>=day(dob)
    age=year(date())-year(dob)
    case else
    age=year(date())-year(dob)-1
    end select
    end function

    However, I recently had need to determine a person's age in years and months, including for babies who are less than a year old. I also needed to allow the user to substitute a future date for the usual system date so that they could easily determine how old someone would be at some date in the future.

    I present the following function here. I hope those more clever than I am can, in replies, improve upon it in terms of efficiency of elegance (maybe there is a wholly different and better way to do it). When the best shows up here I will post it in the code archive section.

    Please improve upon it or find errors.

    Raymond Lyons


    function AgeSTR as C(DOB as D,Date_Now as D)

    '**Note that if one wants just yrs as a numerical value
    '** val(calc->result string from AgeSTR) gives the age in yrs with blanks being 0

    dim ageSTR0 as c
    dim Cur_Month as n
    dim DOB_Month as n
    dim Months_to_add_sub as n

    Cur_Month=month(Date_Now)
    DOB_Month=month(DOB)
    If Cur_month>=DOB_Month
    Months_to_add_sub=-(DOB_Month-Cur_Month)
    else
    Months_to_add_sub=12-(DOB_Month-Cur_Month)
    End If

    select
    case DOB = {}
    ageSTR0="Blank DOB"
    case Date_Now = {}
    ageSTR0= "Current Date is blank"
    case DOB > Date_Now
    ageSTR0="Invalid DOB"

    '**(1A) below is for cur mon is greater than mon of DB
    '**and cur day is greater than or = day of BD
    case month(date_Now)>month(dob).and.day(Date_Now)>=day(dob)
    ageSTR0=Ltrim(STR(year(Date_Now)-year(dob)))+" yrs "+Ltrim(STR(Months_to_add_sub))+" months"

    '**(1B) below is for cur mon is greater than mon of DB
    '**and cur day is less than day of BD
    case month(Date_Now)>month(dob).and.day(Date_Now)= day of BD
    case month(Date_Now)=month(dob).and.day(Date_Now)>=day(dob)
    ageSTR0=Ltrim(STR(year(Date_Now)-year(dob)))+" yrs "+Ltrim(STR(Months_to_add_sub))+" months"

    '**(2B)below is where both dates are in the same month & cur day =day(dob)
    ageSTR0=Ltrim(STR(year(Date_Now)-year(dob)-1))+" yrs "+Ltrim(STR(Months_to_add_sub))+" months"

    '**(3B) below is for cur mon is less than mon of DB
    '**and cur day is less than day of BD (subtract 1 yr & subtract 1 month)
    case month(Date_Now)


  • #2
    RE: Age in yrs and months

    Raymond,

    Try this function; Note that Age= is one long expression line. Make sure it is all together or you should use a line continuation.


    function Age as N(Birthdate as D,CompareDate as D)

    ' Computes difference in years of CompareDate-Birthdate
    ' If CompareDate is blank, it uses current date
    ' Value can return negative ages (which is to the future)

    ' Age({01/01/1999},{})

    IF CompareDate={}
    date1=DATE()
    ELSE
    date1=CompareDate
    END IF

    Age=YEAR(date1)-
    YEAR(Birthdate)+IF(RIGHT(CDATE(Birthdate),4)>RIGHT(CDATE(date1),4),
    (date1-ADDYEARS(Birthdate,YEAR(date1)-YEAR(Birthdate)-1))/365-1,
    (date1-ADDYEARS(Birthdate,YEAR(date1)-YEAR(Birthdate)))/365)

    end function


    Regards,

    Ira J. Perlow
    Computer Systems Design & Associates
    csda@mediaone.net
    Regards,

    Ira J. Perlow
    Computer Systems Design


    CSDA A5 Products
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    Comment


    • #3
      RE: Age in yrs and months

      Thanks Ira,

      I can see that your function results in a decimal. I thought about going that route and then turning the decimal into months. But I really wanted a function that would return years and months without any further converting through calculated fields. But of course there are lots of ways to skin this cat.

      Ray

      Comment


      • #4
        RE: Age in yrs and months

        Raymond, how do you mean to define the age in 'months'?

        If the current system date is June 1.
        And birthdate is May 31 of the current year.

        Is the child one month old? Or do you want the age to be zero months until 30 days have passed (except for February)?

        -- tom

        Comment


        • #5
          RE: Age in yrs and months

          >>Or do you want the age to be zero months until 30 days have passed
          (except for February)?

          Comment


          • #6
            RE: Age in yrs and months

            this function, elapsed_time(), gives the difference between 2 dates in years, months and days:

            function elapsed_time as C(date1 as D,date2 as D)
            dim y1 as n
            dim y2 as n
            dim m1 as n
            dim days as n
            dim d1 as d

            if date1>date2 then
            ' swap the dates
            dim tempd as d
            tempd=date2
            date2=date1
            date1=tempd
            end if
            ' first approximation to year difference

            y1=year(date2)-year(date1)
            if makedate(month(date1),day(date1),year(date2))>date2 then
            y1=y1-1
            m1=month(date2)-month(date1)+12
            else
            m1=month(date2)-month(date1)
            end if

            if m1+month(date1)>12 then
            y2=y1+1
            else
            y2=y1
            end if
            if makedate(mod(month(date1)+m1,12),day(date1),year(date1)+y2)>date2 then
            ' day is too far
            m1=m1-1
            end if

            d1=makedate(mod(month(date1)+m1,12),day(date1),year(date1)+y2)
            days=date2-d1

            elapsed_time=alltrim(str(y1))+" years and "+
            alltrim(str(m1))+" months and "+alltrim(str(days))+" days"

            end function

            Comment


            • #7
              RE: Age in yrs and months

              Peter,

              I think you need to include the makedate function, unless it is something new a beta you are using. In any case it won't work as is in build 230.

              Ray

              Comment


              • #8
                RE: Age in yrs and months

                Peter e-mailed the makedate function to me. Here it is, in case anyone is interested. I'm not sure what, if anything I'll put in the code archive on all this.

                Ray

                function makedate as D(m as N,d as N,y as N)
                ' when give month, day and year parameters, returns the date or the first
                ' preceding date that is a valid date
                ' e.g., makedate(2,29,97) returns {2/28/97}

                if m>12 .or. m

                Comment


                • #9
                  RE: Age in yrs and months

                  Ray,

                  Here is a much easier function to return the results you want;



                  function AgeMonths as N(Date1 as D,CompareDate as D)

                  ' Computes difference in months of CompareDate-Date1
                  ' If CompareDate is blank, it uses current date
                  ' Value can return negative ages (which is to the future)

                  ' Examples of usage
                  ' AgeMonths({01/01/1999},{})
                  ' AgeMonths({01/01/1999},{06/10/1999})

                  ' To compute Age in Years, just divide the result by 12, as in
                  ' AgeMonths({01/01/1999},{})/12

                  AgeMonths=0

                  IF CompareDate={}
                  date2=DATE()
                  ELSE
                  date2=CompareDate
                  END IF

                  IF Day(Date2)>=Day(Date1)
                  AgeMonths=(YEAR(Date2)*12)+MONTH(Date2)-(YEAR(date1)*12)-Month(date1)+ ((Day(Date2)-Day(Date1))/31)
                  ELSE
                  ' Last month from Date2
                  LstMonth=Addmonths(Date2,-1)

                  ' First day of last Month
                  LstMo1st=LstMonth-DAY(LstMonth)+1

                  ' Last day of previous month from date2
                  LstMoLst=Date2-DAY(date2)

                  AgeMonths=(YEAR(Date2)*12)+MONTH(Date2)-(YEAR(date1)*12)-Month(date1)-1+ (Date2-(LstMo1st-1+Min(DAY(LstMoLst),DAY(Date1))))/31
                  END IF

                  end function




                  Regards,

                  Ira J. Perlow
                  Computer Systems Design & Associates
                  csda@mediaone.net
                  Regards,

                  Ira J. Perlow
                  Computer Systems Design


                  CSDA A5 Products
                  New - Free CSDA DiagInfo - v1.39, 30 Apr 2013
                  CSDA Barcode Functions

                  CSDA Code Utility
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                  Comment

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