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Expression Not Working

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    Expression Not Working


    DHI......Calc DHI_PREF substr(DHI,1,3)


    Required To elininate any prefix if it equals
    GMK or contains a "-" (in positions 1 to 3).

    substr(Dhi,1,3) "GMK".and. "-" $ substr(Dhi,1,3)

    The first part of the expression on its own works, it eliminates GMK.

    The second part of the expression eliminates ALL. It appears to find the "-" in positions beyond the third. ps. also tried the second part by itself, same result.

    Any thoughts would be appreciated.

    RE: Expression Not Working

    Looks like a job for nested if expressions.

    See discussion of the IF() function at pg 408 of the xbasic ref. manual.

    -- tom


      RE: Expression Not Working

      Have used nested if's extensively, but not sure why your recommending them for this problem. It appears that the $ expression is not working in the negative eg. NOT EXIST (). Have used this expression many times but always in the positive EXISTS and it has always worked fine. Is it possible that the $ expression can only be used in the positive? Not sure how nested if's will help.




        RE: Expression Not Working

        your second use of "" makes no sense (at least to me).

        i think what you want is something like

        .not. ((substr(Dhi,1,3)="GMK").or.("-"$substr(Dhi,1,3)))


          RE: Expression Not Working

          John, maybe this will help.

          From the interactive editor:

          dim fname as c
          fname = "AAA-10-BBB"

          ?if(*any(substr(fname,1,3),"-"),"Hyphen found","Hyphen not found")
          = "Hyphen not found"
          fname = "AA-10,BBB"
          ?if(*any(substr(fname,1,3),"-"),"Hyphen found","Hyphen not found")
          = "Hyphen found"


            RE: Expression Not Working

            Did the trick, but don't understand why my original construct did not ?

            Thanks, John


              RE: Expression Not Working


              One important difference is .and. vs .or.

              In the former both parts must be true or the entire thing is false. In the latter, either part may be true and the entire thing is true.

              -- tom


                RE: Expression Not Working


                Please pardon the last post. It's clear you know the diff between .and. and .or.

                Instead of
                substr(Dhi,1,3) "GMK".and. "-" $ substr(Dhi,1,3)

                Would this work?
                substr(Dhi,1,3) "GMK".and. .not. "-" $ substr(Dhi,1,3)

                If so, maybe that explains the problem.

                -- tom


                  RE: Expression Not Working


                  Below is what I believe to be the best format for the equation. Note that I use the == operator then .not. it. The not equals operator can operate differently with string comparisons, so .not. a == operator is better for A5 (in my opinion)

                  The $ operator and it's parameters should have parenthesis around it to make sure A5 interprets it properly. There are times it gets confused with the $ operator

                  .not.(substr(Dhi,1,3)=="GMK").and..not.("-" $ substr(Dhi,1,3))

                  But you can't use operators anyway you want as you initially did. The is only valid to compare two parameters (of the same type) on the left and right of it. You were using it as a negate function (a unary operator), which is A5's .not.

                  See ya next month at the A5 Developer's conference!


                  Ira J. Perlow
                  Computer Systems Design & Associates
                  [email protected]

                  Ira J. Perlow
                  Computer Systems Design

                  CSDA A5 Products
                  New - Free CSDA DiagInfo - v1.39, 30 Apr 2013
                  CSDA Barcode Functions

                  CSDA Code Utility
                  CSDA Screen Capture


                    RE: Expression Not Working


                    "-" $ substr(Dhi,1,3) is a logical expression that evaluates to either true or false. Another okay expression would have been:

                    "-" $ substr(Dhi,1,3) = .F.



                      RE: Expression Not Working

                      Tom, Ira, John

                      Thanks ever so much. This last portion of my system has been eluding me for eons. This allows for the crowning glory. Look forward to meeting "you all" at the conference.