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Need a decimal to hex conv function?

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    Need a decimal to hex conv function?

    Don't really know why I started trying to do this, but it seems to work.

    Function in body of post and in attachment.

    function dectohex as C(dec as N)

    � By Stan Mathews
    � Public domain 2002
    � Last update 1/8/02

    dectohex = "" ' Set value to return (null) if input test fails

    if round(dec,0) dec
    ui_msg_box("Invalid input","Hex conversion not defined for fractional values",UI_OK+UI_ATTENTION_SYMBOL)
    end if

    dim global manip[255] as N
    dim global blb as C
    dim global mess as n
    mess = dec
    blb = ""
    i = 0
    while (mess/16)> 1
    i = i + 1
    manip[i] = mod(mess,16)
    mess = floor(mess/16)

    end while

    fstchar = case(mod(mess,16)=0,"0",mod(mess,16)=1,"1",mod(mess,16)=2,"2",mod(mess,16)=3,"3",mod(mess,16)=4,"4",mod(mess,16)=5,"5",mod(mess,16)=6,"6",mod(mess,16)=7,"7",mod(mess,16)=8,"8",mod(mess,16)=9,"9",mod(mess,16)=10,"A",mod(mess,16)=11,"B",mod(dec,mess)=12,"C",mod(mess,16)=13,"D",mod(mess,16)=14,"E",mod(mess,16)=15,"F")

    if i > 0

    for m = i to 1 step -1
    blb = blb + case(manip[m]=0,"0",manip[m]=1,"1",manip[m]=2,"2",manip[m]=3,"3",manip[m]=4,"4",manip[m]=5,"5",manip[m]=6,"6",manip[m]=7,"7",manip[m]=8,"8",manip[m]=9,"9",manip[m]=10,"A",manip[m]=11,"B",manip[m]=12,"C",manip[m]=13,"D",manip[m]=14,"E",manip[m]=15,"F")
    next m

    end if

    dectohex = fstchar + blb

    end function
    There can be only one.

    #2
    RE: Need a decimal to hex conv function?

    Hi Stan,

    This is a previous thread on Decimal to Hexadecimal conversion;

    Dec2Hex routine thread


    Below and attached is my slightly updated version from my previous version in that thread


    function Dec2Hex as C(Number as N)
    'function Dec2Hex as C(Number as N, Places as N) 'Alternative version with Places used
    ' Created by Computer Systems Design & Associates
    ' Copyright 2001 Computer Systems Design & Associates, All Rights Reserved
    ' Last Update: July 7, 2001

    ' Purpose: This function converts Decimal Numbers to HexaDecimal

    ' Input: Decimal Number to convert. It can be a fractional and negative as well.
    ' Places could be passed to set the maximum number of fractional digits to generate

    ' Output:Character string containing hexadecimal equivalent

    ' Errors:Places is negative or Number is not a number (blank number)

    ' Typical Usage:
    ' Dec2Hex(123)
    ' Dec2Hex(-123)
    ' Dec2Hex(123.45)
    ' Dec2Hex(-123.45)
    ' Dec2Hex(numeric_expression)

    ' Examples:
    ' Dec2Hex(1.234)

    ' Notes: None
    '

    ' This contains the maximum number of fractional digits generated
    ' It could be an additional parameter in the function too (Or Optional in version 5)
    places=5

    ' Set inital return value
    Dec2Hex=""

    If 0>=Places.or.Number=MATH_NAN
    END
    End If

    ' Compute the Integer portion
    i=INT(ABS(number))
    h=""
    while i>0
    h=SUBSTR("0123456789ABCDEF",MOD(i,16)+1,1)+h
    i=INT(i/16)
    END WHILE

    ' Compute the Fractional portion
    p=0
    i=ABS(number)-INT(ABS(number))
    IF i>0.and.places>p
    h=h+"."
    while i>0.and.places>p
    j=i*16
    k=INT(j)
    h=h+SUBSTR("0123456789ABCDEF",k+1,1)
    i=j-k
    p=p+1
    END WHILE
    END IF

    ' Add negative if less than 0
    IF 0>number
    h="-"+h
    END IF

    Dec2Hex=h

    end function


    Regards,

    Ira J. Perlow
    Computer Systems Design & Associates
    [email protected]
    Regards,

    Ira J. Perlow
    Computer Systems Design


    CSDA A5 Products
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    Comment


      #3
      RE: Need a decimal to hex conv function?

      I searched the board for "hex" and didn't find anything, although I thought I remembered something.

      Thanks,

      Stan
      There can be only one.

      Comment


        #4
        RE: Need a decimal to hex conv function?

        Correcting myself, I searched the Code Archve and didn't find anything. Your original post is in the Ver 4 board. should have checked there too.

        Thanks again,

        Stan
        There can be only one.

        Comment

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