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Need code for outputting 10 random records to a new file - - from any file structure

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    Need code for outputting 10 random records to a new file - - from any file structure

    We need to create a code for outputting 10 random records to a new file, We will need to use this code on files that have different structure (meaning different field name or field count) which creates a problem since the field count and field name need to be listed if the copy or append operation is used. We appreciate any input on this. Thank you!

    This is the program as it was used in Clipper�
    parameters datafile
    outfile=datafile+"n"

    use &datafile
    copy to &outfile for recno()=int(reccount()/10*1).or.;
    recno()=int(reccount()/10*2).or.;
    recno()=int(reccount()/10*3).or.;
    recno()=int(reccount()/10*4).or.;
    recno()=int(reccount()/10*5).or.;
    recno()=int(reccount()/10*6).or.;
    recno()=int(reccount()/10*7).or.;
    recno()=int(reccount()/10*8).or.;
    recno()=int(reccount()/10*9).or.;
    recno()=int(reccount()/10*10)

    #2
    Re: Need code for outputting 10 random records to a new file - - from any file struc

    Good morning, Jose.

    This kind of question probably belongs in the forum corresponding to the version of Alpha Five you're using. It will get better exposure there, and idiosyncracies based on your version number will be minimized.

    Please clarify or confirm what your input source will be, and what format you want the output target to be. I'm not a clipper head but it seems your goal is to take any arbitrary table (not file) and copy a random selection of records to a new table (not file). Is this right?

    Comment


      #3
      Re: Need code for outputting 10 random records to a new file - - from any file struc

      Tom �
      Good morning and thanks for your reply.

      Yes, you are correct about my goal - (table) should be the word.

      The input and output source will be the same format although at some point I will need to convert both to comma delimited.

      This is my table source and destination code so far�

      tbl_source = table.open("c:\temp\o"+alltrim(runjob->Jobnum)+"1.dbf", FILE_RW_EXCLUSIVE)

      tbl_dest = table.open("c:\temp\o"+alltrim(runjob->Jobnum)+"1n.dbf", FILE_RW_EXCLUSIVE)

      Comment


        #4
        Re: Need code for outputting 10 random records to a new file - - from any file struc

        The random records part is easy since Alpha has a built in random_records() function to use in a query. The tedious part will be iterating through the source table fields with

        tbl.fields_get - to get the count
        fld = tbl.field_get(#) - to get a pointer to each field, consecutively
        fld.name_get() - to get each field's name
        There can be only one.

        Comment


          #5
          Re: Need code for outputting 10 random records to a new file - - from any file struc

          Jose,

          You should investigate using the "Copy" operation. I believe if create one using the designer you'll be able to copy the code that's generated by the designe and then adapt it to your situation. The trick will be coming up with a filter expression that generates a random selection of records. But to begin with read up on "operations", and especially the "copy" operation.

          Later...
          Hey Stan, good morning. I forgot about the random_records() function. Thanks for mentioning it.

          Comment


            #6
            Re: Need code for outputting 10 random records to a new file - - from any file struc

            Stan,

            if your just looking for the list of fields names you can use

            tbl.field_name_get()
            Tim Kiebert
            Eagle Creek Citrus
            A complex system that does not work is invariably found to have evolved from a simpler system that worked just fine.

            Comment


              #7
              Re: Need code for outputting 10 random records to a new file - - from any file struc

              Originally posted by Tim Kiebert View Post
              Stan,

              if your just looking for the list of fields names you can use

              tbl.field_name_get()
              Yeah, and I just remembered

              tbl.create_clone()

              which obviates the need for all that.
              There can be only one.

              Comment


                #8
                Re: Need code for outputting 10 random records to a new file - - from any file struc

                Jose,

                You may also want ot check out the <TBL>.COPY_RECORDS_TO() function. It takes a filter in which you can use the Random_Records() function Stan mentioned.

                EDIT: YEP, good one Stan.

                Maybe first tbl.create_clone() and then tbl.copy_records_to() the newly cloned table.
                Tim Kiebert
                Eagle Creek Citrus
                A complex system that does not work is invariably found to have evolved from a simpler system that worked just fine.

                Comment


                  #9
                  Re: Need code for outputting 10 random records to a new file - - from any file struc

                  Thanks everyone for your replies, please see the code below... for some reason I get this message "table structures do not match. cannot copy records" Please let me know if you have any suggestions. Thanks


                  dim tbl_source as P
                  dim filename as C
                  dim qry as P

                  tbl_source = table.open("c:\temp\o"+alltrim(runjob->Jobnum)+"1.dbf")
                  filename = "c:\temp\o"+alltrim(runjob->Jobnum)+"1n.dbf"
                  tbl_source.create_clone(filename)

                  tbl_source = table.current()

                  query.description = "nth"
                  query.order = ""
                  query.filter = random_pct_record_list(10)
                  query.options = ""
                  qry = tbl_source.query_create()
                  tbl_dest = tbl_source.copy_records_to(filename,"nth")

                  Comment


                    #10
                    Re: Need code for outputting 10 random records to a new file - - from any file struc

                    Originally posted by JLG View Post
                    Thanks everyone for your replies, please see the code below... for some reason I get this message "table structures do not match. cannot copy records" Please let me know if you have any suggestions. Thanks


                    dim tbl_source as P
                    dim filename as C
                    dim qry as P

                    tbl_source = table.open("c:\temp\o"+alltrim(runjob->Jobnum)+"1.dbf")
                    filename = "c:\temp\o"+alltrim(runjob->Jobnum)+"1n.dbf"
                    tbl_source.create_clone(filename)

                    tbl_source = table.current()

                    query.description = "nth"
                    query.order = ""
                    query.filter = random_pct_record_list(10)
                    query.options = ""
                    qry = tbl_source.query_create()
                    tbl_dest = tbl_source.copy_records_to(filename,"nth")
                    You have two lines which do the same thing.

                    Code:
                    [COLOR="Red"]tbl_source = table.open("c:\temp\o"+alltrim(runjob->Jobnum)+"1.dbf")[/COLOR]filename = "c:\temp\o"+alltrim(runjob->Jobnum)+"1n.dbf"
                    tbl_source.create_clone(filename)
                    
                    [COLOR="red"]tbl_source = table.current()[/COLOR]
                    I think the second one is causing the trouble.
                    There can be only one.

                    Comment


                      #11
                      Re: Need code for outputting 10 random records to a new file - - from any file struc

                      This is what i was looking for. Thanks everyone.

                      tbl_source.create_clone(filename)
                      result = tbl_source.copy_records_to(filename,"random_records(10,\".t.\")" )

                      Comment

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