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Duplicate a DistinctCount from Crystal Report

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    Duplicate a DistinctCount from Crystal Report

    I have a crystal reports to convert to Alpha reports. Data is in Excel.

    The crystal reports is using a function called DistinctCount. It returns the number of distinct tuples in a set. Empty cells are not included in the count. Returns a numeric value.

    The formula takes an array with five date columns and counts unique "Dates" included for Year = 2009. See attached file for display.

    Mock Sample code from crystal:
    Result Value: = DistinctCount{[Year(Date1)= “2009”,Year(Date2)=”2009”, Year(Date3)=”2009”, Year(Date4)=”2009”, Year(Date5=”2009”]}

    Does Alpha have a function to do this ? Code sample please.

    Thanks.
    Last edited by harrison4411; 04-05-2010, 04:01 PM.

    #2
    Re: Duplicate a DistinctCount from Crystal Report

    One of Alpha strengths is the ability to define your own functions.

    One way to have that distinct count available for your report is to store the count in a field and refresh it before running the report. Given my attached table this function will do that.

    Code:
    FUNCTION dcount AS N (tablename AS C, year AS N )
    	tbl = table.open("dts")
    	tbl.order("recno()")
    	tbl.fetch_first()
    	while .not. tbl.fetch_eof()
    		tst = table.external_record_content_get(tablename,"dtoc(d1)+crlf()+dtoc(d2)+crlf()+dtoc(d3)+crlf()+dtoc(d4)+crlf()+dtoc(d5)","recno()","recno() = "+tbl.recno())
    		cnt = 0
    		FOR t = 1 TO 5
    			td = word(tst,t,crlf())
    			IF year(ctod(word(tst,t,crlf()))) <> year
    				tst = word_subtract(tst,td,crlf())
    			END IF
    			IF  word_occurs(tst,td,crlf())> 1
    				cnt = cnt+1
    				tst = word_subtract(tst,td,crlf())
    			END IF
    		NEXT t
    		tbl.change_begin()
    		tbl.Dcount = cnt
    		tbl.change_end(.t.)
    		tbl.fetch_next()
    	end while
    	tbl.close()
    END FUNCTION
    It should also be possible to make a report calculated field and modify the function to process the count on the fly.

    Edit: I don't think I fully understood what should be counted. Working on a function modification.
    Last edited by Stan Mathews; 04-05-2010, 05:04 PM.
    There can be only one.

    Comment


      #3
      Re: Duplicate a DistinctCount from Crystal Report

      How did you run the funct : I don't see any Code file under the code tab.

      I would like to make it a calculated field in the report if you can show me that also.

      Your example on row 3 is :
      1/1/09, 1/2/09, 1/3/09, 1/4/09, 1/1/09 should display a count of 4. The formula you have displays 1.

      My formula in crystal I first check is the field for the year 2009 and if so then compare other 2009 dates making sure that the date is also not counted in another date column thus deing a duplicate date just need to count the single occurance.

      Also if a date field is black/empty/null it should still calculate the Dcount column.

      Example of counts.
      null, 1/2/09, 1/3/09, 1/4/09, 1/1/09 should display 4 count.

      1/1/08, 1/2/09, 1/3/09, 1/4/09, 1/1/09 should display 4 count

      1/1/08, 1/2/09, 1/3/09, 1/4/09, 1/1/08 should display 3 count

      Thanks
      Last edited by harrison4411; 04-05-2010, 06:22 PM.

      Comment


        #4
        Re: Duplicate a DistinctCount from Crystal Report

        I think this is the corrected function. Usage example for my sample table....

        dcount("dts",2009)

        Could be run from a button.


        Code:
        FUNCTION dcount AS N (tablename AS C, year AS N )
        	tbl = table.open(tablename)
        	tbl.order("recno()")
        	tbl.fetch_first()
        	while .not. tbl.fetch_eof()
        		tst = table.external_record_content_get(tablename,"dtoc(d1)+crlf()+dtoc(d2)+crlf()+dtoc(d3)+crlf()+dtoc(d4)+crlf()+dtoc(d5)","recno()","recno() = "+tbl.recno())
        		cnt = 0
        		newtst = ""
        		while tst > ""
        			td = word(tst,1,crlf())
        		    if year(ctod(td)) <> year
        				tst = word_subtract(tst,td,crlf())
        			else
        				newtst = newtst+word(tst,1)+crlf()
        				tst = word_subtract(tst,td,crlf())
        			END IF
        		end while
        		while newtst > ""
        			td = word(newtst,1,crlf())			
        			cnt = cnt+1
        			newtst = word_subtract(newtst,td,crlf())
        		end while
        		tbl.change_begin()
        		tbl.Dcount = cnt
        		tbl.change_end(.t.)
        		tbl.fetch_next()
        	end while
        	tbl.close()
        END FUNCTION
        There can be only one.

        Comment


          #5
          Re: Duplicate a DistinctCount from Crystal Report

          Here's a function tha could be used for a calculated field rule or a calculated field on a form.

          Code:
          FUNCTION dcfunct AS N (year AS N )
          	dcfunct = 0
          	newtst = ""
          	tbl = table.current()
          	tst = dtoc(tbl.d1)+crlf()+dtoc(tbl.d2)+crlf()+dtoc(tbl.d3)+crlf()+dtoc(tbl.d4)+crlf()+dtoc(tbl.d5)
          	FOR each foo in tst
          		IF year(ctod(foo))= year
          			newtst = newtst+foo+crlf()
          		END IF
          	next
          	dcfunct = w_count(word_unique(newtst,crlf()),crlf())
          END FUNCTION
          There can be only one.

          Comment


            #6
            Re: Duplicate a DistinctCount from Crystal Report

            stan, thank you. I like this method.

            I was looking into *remove_duplicates() function.

            Comment

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