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Programming Puzzle 7 - Yet another nested loop!

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    Programming Puzzle 7 - Yet another nested loop!

    Beginning Xbasic Programming

    Puzzle 7 - Yet Another Nested loop

    You solved Puzzle_6, but your sales manager tells you that she forgot something
    that she needs. She doesn't really care how many separate invoices an item
    might have been on, she wants to know the amount of money each product generated.

    Just like a manager, right?

    Your job now is to write an xbasic script that will list each product
    and for each product show the total dollars generated by that item
    across all the invoices.

    Instructions:

    a) you may not use any of the built in summary functions, methods,
    or operations in Alpha Five. We're doing this one by hand.

    b) you may open the table only once

    c) your output should be directed to the trace window

    d) your list should be in ascending order based on the Product_id field

    #2
    Re: Programming Puzzle 7 - Yet another nested loop!

    As before.

    puzzle seven.txt
    There can be only one.

    Comment


      #3
      Re: Programming Puzzle 7 - Yet another nested loop!

      At about this time, I would opt to train the manager in how to design reports.

      Code:
      'Date Created: 09-Jun-2011 11:29:00 AM
      'Last Updated: 09-Jun-2011 04:16:52 PM
      'Created By  : andy
      'Updated By  : andy
      OPTION STRICT
      OPTION ENCRYPTED_TOKENS
      ON ERROR GOTO ERR_HANDLER
      
      DIM vInvoice_ItemsP as P
      
      DIM vOrderC as C
      DIM vFilterC as C
      DIM vFormatC as C
      
      DIM vIndxN as N
      
      DIM arrInvoice[0] as P
      DIM arrInvoice[0].ProductC as C
      DIM arrInvoice[0].ExtensionN as N
      vInvoice_ItemsP = table.open("invoice_items",FILE_RW_SHARED)
      	vOrderC = "Product_id"
      	vInvoice_ItemsP.order(vOrderC)
      	vInvoice_ItemsP.fetch_first()
      	WHILE .not. vInvoice_ItemsP.fetch_eof()
      		vIndxN = arrInvoice.find(vInvoice_ItemsP.Product_Id, "ProductC")
      		IF vIndxN > 0 THEN
      			'Product found
      			arrInvoice[vIndxN].ExtensionN = arrInvoice[vIndxN].ExtensionN + vInvoice_ItemsP.extension
      		ELSE	
      			'Product not Found
      			arrInvoice[].ProductC = vInvoice_ItemsP.product_id
      			arrInvoice[..].ExtensionN = vInvoice_ItemsP.extension
      		END IF
      		vInvoice_ItemsP.fetch_next()
      	END WHILE
      vInvoice_ItemsP.close()
      
      vFormatC = "ProductC|ExtensionN"
      trace.WriteLn(arrInvoice.dump_properties(vFormatC))
      
      
      
      
      
      END
      '-----------------------------------
      'Error handler
      '-----------------------------------
      ERR_HANDLER:
      	Dim err as N= error_code_get()
      	Dim msg as C= "Error # "+ err + crlf() + error_text_get(err)
      	msg = msg + crlf() + "Script: " + error_script_get()
      	msg = msg + crlf() + "Line #: " + error_line_number_get()
      
      	trace.writeln(msg)
      
      	ui_msg_box("Error", msg, ui_attention_symbol)
      	msg = ""
      	
      	END
      Andrew

      Comment


        #4
        Re: Programming Puzzle 7 - Yet another nested loop!

        Here's my solution.

        The attachment is the "exported" script. In this format the script can be easily "imported" into your copy of the puzzle database.

        -- tom

        Comment


          #5
          Re: Programming Puzzle 7 - Yet another nested loop!

          puzzle attempt for puz 7!

          puz7.txt

          Comment

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