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Thread: Refresh Linked Grids/Content

  1. #1
    Member
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    John Azzara
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    Aug 2011
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    Default Refresh Linked Grids/Content

    Hello,

    I was wondering if there is a way to refresh a grid when a tab is clicked. Specifically, I have 7 linked grids that I built using the Linked Content Builder. Each grid is linked to the same parent. One of the child grids (grid A) updates information in one of the other child grids (grid B) via OnAfterSQLCommandExecute event. However when I click on the tab that contains grid B the information is not updated. If I manually refresh the information displays. I was hoping to have grid B automatically refresh when the tab is clicked - grid B is the only tab out of the 7 that I need to refresh every time on tab click in case any updates have been made to grid A.

    I have created a process where grid A gets a pointer to its parent object and refreshs the parent causing all of the grids to refresh which gets me what I want however, I was hoping there might be a way to just refresh on tab click instead of having to refresh the parent object?

  2. #2
    Member
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    David Bruck
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    Mar 2011
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    Huron, Ohio
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    Default Re: Refresh Linked Grids/Content

    Hi John

    I ran into the same thing this morning (child grid that has sql updates done in either the OnAfterSQLCommandExecute or AfterUpdateRecord events) and need the parent grid to display some of the data updated by the child grids SQL update. I found numerous posts on the message board with no answers on how to handle this particular condition, so thought it'd be good to followup with what worked for me

    in the child grids "Properties" -> "Javascript - System Events"
    if (e.hasErrors == false) closeParentA5Window('correctionpopup');
    //Get a pointer to the parent Grid object that opened this Grid and execute a .refresh() method on the parent.
    var po = {grid.object}.getParentObject();
    //If this Grid does not have a parent then 'po' will be false.
    if(po) po.refresh()

    The 1st statement closes the child grid - the other 2 statements do the parent grid refresh and works great

  3. #3
    Member
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    John Azzara
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    Aug 2011
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    Default Re: Refresh Linked Grids/Content

    Hi David,

    Thanks for the reply. I actually ended up creating individuals button links instead of using the linked content builder. It gave me greater control over the look and feel and I was able to stack one set of buttons on top of the others by customizing the action button section at the bottom of the grid. The linked content builder would only display the tabs in one long row. Futhermore I could declaritivly set the buttons to cache or not to cache. Thanks again for the reply. BTW what system event did you use?

  4. #4
    Member
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    David Bruck
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    Mar 2011
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    Huron, Ohio
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    Default Re: Refresh Linked Grids/Content

    The buttons/links in this case are part of the rows defined in the grid and use the AfterUpdateRecord event to perform the additional SQL database updates. The Linked Content option isn't involved because just like you, I need to do more customization than can be had through the built in feature

  5. #5
    "Certified" Alphaholic TheSmitchell's Avatar
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    Sarah
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    Apr 2012
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    Default Re: Refresh Linked Grids/Content

    Digging up an old topic. I just want to refresh the tab in question, as the OP mentions. I didn't want to do it with calls through the parent object or extra buttons and what not. So, I did did a bit of FireBug investigation to figure out how to register an event handler when the tabs for the relevant pane(s) are clicked.

    In my onGridInitialize event - because you only want to register the event once! - I added the following (note: my "NAME_OF_LINKED_CONTENT_SECTION" is EmpHours; you will need to replace EmpHours with your content section's name):
    Code:
    // define event handler for pane tab click
    var onPane1Click = function () {
        //Panes are 0 indexed:
        //  0 = pane 1
        //  1 = pane 2
        //  etc...
        //Must quote pane number
        var paneGridObj = window[{grid.object}._linkedGrids.EmpHours["0"] + "_GridObj"];
        if (typeof (paneGridObj) !== 'undefined') {
            paneGridObj.refresh();
        }
        return;
    }
    
    // register event handler with pane tab's click event
    $e.add('{grid.componentName}_LCS_EMPHOURS.0.TAB','click',onPane1Click);
    The component name of the linked content grids are stored in {grid.object}._linkedGrids.NAME_OF_LINKED_CONTENT_SECTION:
    linkedContentSection.png

    Name is case sensitive, so you want to match exactly.

    The ID for each pane tab, you use "{grid.componentName}_LCS_" + The name of your Linked content section all upper case + "." + Pane number (starts at 0) + ".TAB".

    Each {grid.object} is stored in the window. You can get the grid object using window[{grid.componentName} + "_GridObj"]. The {grid.componentName} for the grid in each pane is in the {grid.object}._linkedGrids.NAME_OF_LINKED_CONTENT_SECTION object.

    Hope this helps someone.
    ---
    Sarah
    Alpha Anywhere latest pre-release

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