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Include Parent in report if Child filter satisfied

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    Include Parent in report if Child filter satisfied

    My application records service calls on customers' office equipment. I need to create an "excess service calls" report that will include only records that satisfy a child-level filter.

    Parent db is 'Machines' and Child db is 'Calls'. The user would be prompted for two filter parameters, "X" and "Y". The report includes only those machines where there were at least "X" number of service calls done over the last "Y" days -- i.e. at least 3 calls in the last 30 days.

    The group breaks on a change in Machine_id and the report detail includes information about each call, but only machines that satisfy this "3 in 30" filter are included in the report. And the detail includes only those calls that happened within the "Y" parameter, i.e. within the last 30 days.

    Can anyone help me create this filtering scenario please?

    #2
    Re: Include Parent in report if Child filter satisfied

    Assuming the report layout is presently based on a set using a one-to-many link I suggest you create a new set for the same tables, but reverse (invert) the relationships. Make the child table parent, and link to the parent table (as child) using a 1:1 linkage. Then base your report layout on the new set, filtering the "new" parent table as required.

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      #3
      Re: Include Parent in report if Child filter satisfied

      Originally posted by Tom Cone Jr View Post
      Assuming the report layout is presently based on a set using a one-to-many link I suggest you create a new set for the same tables, but reverse (invert) the relationships. Make the child table parent, and link to the parent table (as child) using a 1:1 linkage. Then base your report layout on the new set, filtering the "new" parent table as required.
      Thanks, Tom
      That makes a lot of sense, but I'm not sure how to create this "3 in 30" filter. The date part is easy, but including only those records for each machine_id if there are at least 3 such records in that time span? That part I'm lost on...

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        #4
        Re: Include Parent in report if Child filter satisfied

        Jeffrey,

        Consider using a filtered tablecount() equal to or greater than the specified minimum.

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          #5
          Re: Include Parent in report if Child filter satisfied

          Originally posted by Tom Cone Jr View Post
          Jeffrey,

          Consider using a filtered tablecount() equal to or greater than the specified minimum.
          Tom,
          I'm not a beginner at this, but I may be a bit dense. I can't visualize how to make tablecount() work, but I guess we'd have to loop through the entire Machine table, testing each machine to see if there are more than X calls in Y date range in the Calls table? Or somehow have the function return a list of each machine_id in the Calls table that satisfies the criteria? Any help writing functions that do this is greatly appreciated...

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            #6
            Re: Include Parent in report if Child filter satisfied

            Oh. mea culpa.

            I see what you mean. You could use the tablecount() function to either run or not run a report for a single machine.... but not to determine whether a particular machine should be included in a report covering all machines. Sorry.

            Give us some sample data to work with. I'm thinking of a script that loops through the machines and "marks" those which have children meeting the filter criteria. Your report, based on the inverted set I mentioned above, would then be filtered to include only the marked machine records.

            ----------------
            Later on
            ----------------

            Since the tablecount() function must open a new instance of the table each time it's called it's relatively slow. If your table is large you may want to simply open the table once, query it for the pertinent date range, then step through the filtered table (sorted by machine id) marking machine records (in the other table) as you go. Probably would be faster.
            Last edited by Tom Cone Jr; 02-20-2007, 04:40 PM. Reason: New idea

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