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Can anyone help me with this expression?

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    #16
    Re: Can anyone help me with this expression?

    Originally posted by jdoyle View Post
    Stan,
    Thanks, the code worked, but it does not store the calulated points.
    When you enter how the animal placed and go to the next field (ALSA_points) it shows the points but will not save the points in that field.
    Any suggestions?
    Jim
    To save that value you could have a calculated field in the table, not in the browse or on the form. The same expression would suffice.

    The problem with this approach is that the value is only recalculated when something in the same record changes which affects the calculation (patently impossible). As each new record is added you would need to do something to recalculate the field in all records. (Not sure if that is available in A4). You could re-evaluate the field rules from the control panel, but that is clumsy.

    I would suggest you make this a batch process. When you need the points value stored/recalculated for the records in the table, run an update operation on the field with the (now working) expression.

    But do you really need it stored?
    There can be only one.

    Comment


      #17
      Re: Can anyone help me with this expression?

      Stan,
      Thanks for your help.
      I am new to ALPHA5 and your instructions has taught me alot. It would have taken for ever to learn. The expression works fine and I got it to store in another *.dbf. with one little problem. After in put in form "Show Ring Entry" I get an error "Error posting to table llama data". However you go look at the llama data and the new information is there. Any suggestions?

      I don't know who this message board is sponsored by, but it is a great help.

      Thanks agin
      Jim

      Comment


        #18
        Re: Can anyone help me with this expression?

        Stan,
        You were kind enough to help me with this expression. It works ok, but I have run in to a problem. Example: There could be a class with 17 llamas shown in the class. The association rules that the judge must place 6 out of the class of 17. When you enter the placeings 1 thru 6 it calculates the points correctly. The other llamas shown get no points. So if the "placed" field for the other llamas is left blank it awards 6 points. These llamas that don't place are dismissed from the show ring and are not placed. However all llamas not placeing beyond 6th are given 6 points in the ALSA field. My question is if the other 9 llamas did not place how do I get the ALSA points to be 0 or blank.

        I have attached my data base as crude as it is if you care to look at it. You will find the examples under Show ring entry, also attached the place.doc for award points.

        I also think that I have post this question in the wrong section. I am using Alpha5 v8 Pro

        Thanks
        Jim

        If you can help if would be appreciated

        Comment


          #19
          Re: Can anyone help me with this expression?

          Originally posted by jdoyle View Post
          Stan,
          You were kind enough to help me with this expression. It works ok, but I have run in to a problem. Example: There could be a class with 17 llamas shown in the class. The association rules that the judge must place 6 out of the class of 17. When you enter the placeings 1 thru 6 it calculates the points correctly. The other llamas shown get no points. So if the "placed" field for the other llamas is left blank it awards 6 points. These llamas that don't place are dismissed from the show ring and are not placed. However all llamas not placeing beyond 6th are given 6 points in the ALSA field. My question is if the other 9 llamas did not place how do I get the ALSA points to be 0 or blank.

          I have attached my data base as crude as it is if you care to look at it. You will find the examples under Show ring entry, also attached the place.doc for award points.

          I also think that I have post this question in the wrong section. I am using Alpha5 v8 Pro

          Thanks
          Jim

          If you can help if would be appreciated
          I don't have V8 so I can't open parts of your database that use specific new features.

          As to the logic of your question, can you restate it. I got lost with 6, of 17 and then "tho other 9 llamas". Doesn't add up for me.
          There can be only one.

          Comment


            #20
            Re: Can anyone help me with this expression?

            Sorry that should be other 11 llamas that did not place.
            Jim

            Comment


              #21
              Re: Can anyone help me with this expression?

              Originally posted by jdoyle View Post
              Sorry that should be other 11 llamas that did not place.
              Jim
              I think I'm still lost. If you want 0 points for all llamas that do not have a placed value....

              Code:
              case(placed = 0,0,between(tablecount("llama data","Classid = "+Classid),3,4).and.placed = 1,max(placed,0),tablecount("llama data","Classid = "+Classid)=5,max(3-placed,0),tablecount("llama data","Classid = "+Classid)=6,max(4-placed,0),tablecount("llama data","Classid = "+Classid)=7,max(5-placed,0),between(tablecount("llama data","Classid = "+Classid),8,15),max(6-placed,0),between(tablecount("llama data","Classid = "+Classid),16,23),max(7-placed,0),between(tablecount("llama data","Classid = "+Classid),24,31),max(8-placed,0),between(tablecount("llama data","Classid = "+Classid),32,39),max(9-placed,0),tablecount("llama data","Classid = "+Classid)>39,max(10-placed,0))
              There can be only one.

              Comment


                #22
                Re: Can anyone help me with this expression?

                Yes, all llamas that do not have a value in place field will have a 0 in ALSA_points field.

                If I am clear where is the code in to last reply put in relation to the code for awarding points?
                Jim

                Comment


                  #23
                  Re: Can anyone help me with this expression?

                  Originally posted by jdoyle View Post
                  Yes, all llamas that do not have a value in place field will have a 0 in ALSA_points field.

                  If I am clear where is the code in to last reply put in relation to the code for awarding points?
                  Jim
                  That expression replaces the previous suggestion. It merely checks first to see if the placed field is empty and awards 0 points. After that it maintains the previous calculation.
                  There can be only one.

                  Comment


                    #24
                    Re: Can anyone help me with this expression?

                    Stan,
                    The last code worked perfect. The saying about teaching an old dog new tricks can apply to me. I am 67 and and enjoying every minute of learning new tricks. I am obsessed with Alpha5 v8.

                    Thanks again for your help
                    Jim

                    Comment


                      #25
                      Re: Can anyone help me with this expression?

                      Originally posted by jdoyle View Post
                      Stan,
                      The last code worked perfect. The saying about teaching an old dog new tricks can apply to me. I am 67 and and enjoying every minute of learning new tricks. I am obsessed with Alpha5 v8.

                      Thanks again for your help
                      Jim
                      And you hang out with a bunch of odd looking fuzzy animals. Pluses and minuses in everyones life, I suppose.
                      There can be only one.

                      Comment


                        #26
                        Re: Can anyone help me with this expression?

                        what can I say.
                        Check us out at www.marikollamas.com
                        Jim

                        Comment

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